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In a silicon transistor, the base current is changed by 20 μA. This results in a change of 0.02 V in base to emitter voltage and a change of 2 mA in the collector current. The transistor is used as an amplifier with the load resistance of 5 kΩ. The change in output voltage across load is

a
20 V
b
10 V
c
100 v
d
5 V

detailed solution

Correct option is B

Input resistance  Rin=0.0220×10−6=2×10420Ω=103ΩChange in output across load = 5000 x 0.002 V = 10 V

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In the circuit shown, the base current is 30 µA. The value of R1 is (Neglect VBE)


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