In simple harmonic motion how many times potential energy is equal to kienetic energy during one complete period?

If frequency of oscillation is f, then frequency of potential or kinetic energy is 2f. Now, K=12mω2A2sin2ωt and U=12mω2A2cos2ωtWhen K=U, 12mω2A2sin2ωt=12mω2A2cos2ωt⇒tanωt=±1, ⇒ωt=π4,3π4,5π4,7π4So in a cycle K=U, at t=π4ω,3π4ω,5π4ω,7π4ω.