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Questions  

A simple harmonic oscillator has a period of 0.01 sec and an amplitude of 0.2 m. The magnitude of the velocity in msec1  at the centre of oscillation is

a
20π
b
100
c
40π
d
100π

detailed solution

Correct option is C

At centre vmax=aω=a.2πT=0.2×2π0.01=40π

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