Questions
In a simple harmonic oscillator, at the mean position is
a
KE maximum, PE maximum
b
KE is minimum, PE is maximum
c
KE is maximum, PE is minimum
d
both KE and PE are minimum
detailed solution
Correct option is C
We know KE=12mω2A2-x2 PE=12mω2x2, here m=mass of oscillator, ω=angular frequency,A=amplitude,x=displacementAt mean position x=0KE=12mω2A2(maximum)PE=0 (minimum).**** For a simple harmonic oscillator at mean position potential energy is minimum but not equal to zero.Its total energy =min P.E + max K.E=max P.ETalk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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