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A simple harmonic wave having an amplitude a and time period T is represented by the equation y=5sinπ(t+4)m. Then the value of amplitude (a) in (m) and time period (T) in second are

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a

a=10, T=2

b

a=5, T=1

c

a=10,T=1

d

a=5, T=2

answer is D.

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Detailed Solution

y=5sin(π t+4π), comparing it with standard equation y=asin(ω t+φ)=asin2 π tT+φa=5 m and 2 π tT=π t⇒T = 2 sec.

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