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A simple pendulum is being used to determine the value of acceleration due to gravity ‘g’ at a certain place. The length of the pendulum is measured as 25.0 cm and a stop watch with 1s resolution measures the time taken for 40 oscillations to be 50s. The accuracy in ‘g’ is :

a
2.40%
b
5.40%
c
3.40%
d
4.40%

detailed solution

Correct option is D

Time period = T=2πLg​⇒g=4π2LT2​⇒Δgg=2ΔTT+ΔLL=2150+0.125.0=0.044​⇒Δgg×100=4.4%

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