Q.

A simple pendulum is being used to determine the value of gravitational acceleration ‘g’ at a certain place. The length of the pendulum is 20.0 cm known to 1mm accuracy and a stop watch with 1s resolution measures the time taken for 40 oscillations to be 50s. The accuracy in g is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

3.5%

b

5.5%

c

4.5%

d

2.4%

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

T=2πlg​on squaring both sides​g=4π2lT2​on differentiating,​Δgg=Δll+2ΔTT=0.120+2×150=0.045 ⇒Δgg×100=0.045​ ×100        ∴%Δgg=4.5%
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon
A simple pendulum is being used to determine the value of gravitational acceleration ‘g’ at a certain place. The length of the pendulum is 20.0 cm known to 1mm accuracy and a stop watch with 1s resolution measures the time taken for 40 oscillations to be 50s. The accuracy in g is