First slide

Mechanical energy conservation

Question

A simple pendulum bob has a mass “m” and length “L”. The bob is drawn aside such that the string is horizontal and then it is released. The velocity of the bob while it crosses the equilibrium position is

Easy

A

$\sqrt{g L}$
B

$\sqrt{2 g L}$
C

$\sqrt{5 g L}$
D

$\sqrt{3 g L}$

Solution

$\frac{M V^{2}}{2} = M g L V = \sqrt{2 g L}$

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