A simple pendulum $$50$$ cm long is suspended from the roof of a cart accelerating in the horizontal direction with constant acceleration $$3$$ g $$m/s2$$. The period of small oscillations of the pendulum about its equilibrium position is (g$$ $$=$$ π$$2m/s2):

Question

A simple pendulum $$50$$ cm long is suspended from the roof of a cart accelerating in the horizontal direction with constant acceleration $$3$$ g $$m/s2$$. The period of small oscillations of the pendulum about its equilibrium position is (g$$ $$=$$ π$$2m/s2):

Infinity Learn · Accepted Answer

With respect to the cart, equilibrium position of the pendulum is shown.If displaced by small angle θ from this position, then it will execute SHM about this equilibrium position, time period of which is given by:T $$=$$ $$2$$$$π$$Lgeff; geff $$=$$ $$g2+(3g)2$$⇒geff $$=$$ $$2g$$   ⇒ T $$=1.0$$ second

A simple pendulum 50 cm long is suspended from the roof of a cart accelerating in the horizontal direction with constant acceleration $\sqrt{3}$ g $m / s^{2}$ . The period of small oscillations of the pendulum about its equilibrium position is ( $g = π^{2} m / s^{2}$ ):

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A simple pendulum 50 cm long is suspended from the roof of a cart accelerating in the horizontal direction with constant acceleration 3 g m/s2. The period of small oscillations of the pendulum about its equilibrium position is (g = π2m/s2):

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A simple pendulum 50 cm long is suspended from the roof of a cart accelerating in the horizontal direction with constant acceleration $\sqrt{3}$ g $m / s^{2}$ . The period of small oscillations of the pendulum about its equilibrium position is ( $g = π^{2} m / s^{2}$ ):