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Questions  

 A simple pendulum crosses the highest point of a vertical circle with critical speed. What will be  the centripetal acceleration of the bob, when the string is horizontal?

a
g
b
2 g
c
3 g
d
2.5 g

detailed solution

Correct option is C

if it is critical velocity then at the lowest point it is 5gl at the horizontal position it will be 3gl from conservation of energy 12mv20=12mv2+ mgl    ⇒12m5gl-mgl = 32mgl =12mv2   centrepetal acceleration v2l= 3g

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Similar Questions

A pendulum of length / = l m is released from θ0 = 600. The rate of change of speed of the bob at θ = 300 is (g = 10 m/s2)


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