Q.

A simple pendulum crosses the highest point of a vertical circle with critical speed. What will be  the centripetal acceleration of the bob, when the string is horizontal?

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a

g

b

2 g

c

3 g

d

2.5 g

answer is C.

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Detailed Solution

if it is critical velocity then at the lowest point it is 5gl at the horizontal position it will be 3gl from conservation of energy 12mv20=12mv2+ mgl    ⇒12m5gl-mgl = 32mgl =12mv2   centrepetal acceleration v2l= 3g
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A simple pendulum crosses the highest point of a vertical circle with critical speed. What will be  the centripetal acceleration of the bob, when the string is horizontal?