Questions
A simple pendulum is hanging from a peg inserted in a vertical wall. Its bob is stretched in horizontal position from the wall and is left free to move. The bob hits on the wall the coefficient of restitution is . After how many collisions the amplitude of vibration will become less than 60°
detailed solution
Correct option is B
From the relation of restitution hnh0=e2n and hn=h0(1−cos60°)⇒hnh0=1−cos60°=252n⇒1−12=45n⇒12=45nTaking log of both sides we get log1−log2=n(log4−log5)0−0.3010=n(0.6020−0.6990)− 0.3010=−n×0.097⇒n=0.30100.097=3.1≈3Similar Questions
Two simple pendulums whose lengths are 100 cm and 121 cm are suspended side by side. Their bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum, will the two be in phase again
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