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A simple pendulum has time period T1. The point of suspension is now moved upward according to equation y=kt2  where k=1m/sec2. If new time period is T2 then ratio T12T22  will be

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detailed solution

Correct option is C

y=Kt2⇒d2ydt2=ay=2K=2×1=2m/s2∵K=1m/s2Now, T1=2πlg and  T2=2πl(g+ay)Dividing, T1T2=g+ayg⇒65⇒T12T22=65

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