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Q.

A simple pendulum has time period T1 The point of suspension is now moved upward according to equation y=kt2, where k = 1 m/sec2. If new time period is T2 then ratio T12T22 will be

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a

2/3

b

5/6

c

6/5

d

3/2

answer is C.

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Detailed Solution

y=kt2⇒d2ydt2=ay=2K=2⇒1=2m/s2∵k=1m/s2 Now, T1=2πlg and T2=2πlg+ay Dividing, T1T2=g+ayg⇒65⇒T12T22=65
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