A simple pendulum has time period $$T1$$. The point of suspension is now moved upward according to equation y $$=$$ $$kt2$$ where k $$=$$ $$1$$ $$m/sec2$$. If new time period is $$T2$$, then ratio $$T12T22$$ will be

Question

A simple pendulum has time period $$T1$$. The point of suspension is now moved upward according to equation y $$=$$ $$kt2$$ where k $$=$$ $$1$$ $$m/sec2$$. If new time period is $$T2$$, then ratio $$T12T22$$ will be

Infinity Learn · Accepted Answer

y $$=$$ $$Kt2$$  ⇒ $$d2ydt2$$ $$=$$ ay $$=$$ $$2K$$ $$=$$ $$2$$×$$1$$ $$=$$ $$2$$ $$m/s2$$                                                                                   $$($$∵ K $$=$$ $$1$$ $$m/s2)Now$$, $$T1$$ $$=$$ $$2$$$$π$$lg  and $$T2$$ $$=$$ $$2$$$$π$$$$l(g+ay)Dividing$$, $$T1T2$$ $$=$$ $$g+ayg$$ $$=$$ $$65$$  ⇒ $$T12T22$$ $$=$$ $$65$$

A simple pendulum has time period $T_{1}$ . The point of suspension is now moved upward according to equation y = k $t^{2}$ where k = 1 $m / \sec^{2}$ . If new time period is $T_{2}$ , then ratio $\frac{T_{1}^{2}}{T_{2}^{2}}$ will be

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A simple pendulum has time period T1. The point of suspension is now moved upward according to equation y = kt2 where k = 1 m/sec2. If new time period is T2, then ratio T12T22 will be

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A simple pendulum has time period $T_{1}$ . The point of suspension is now moved upward according to equation y = k $t^{2}$ where k = 1 $m / \sec^{2}$ . If new time period is $T_{2}$ , then ratio $\frac{T_{1}^{2}}{T_{2}^{2}}$ will be