A simple pendulum has time period T1. The point of suspension is now moved upward according to equation y = kt2 where k = 1 m/sec2. If new time period is T2, then ratio T12T22 will be
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a
23
b
56
c
65
d
32
answer is C.
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Detailed Solution
y = Kt2 ⇒ d2ydt2 = ay = 2K = 2×1 = 2 m/s2 (∵ K = 1 m/s2)Now, T1 = 2πlg and T2 = 2πl(g+ay)Dividing, T1T2 = g+ayg = 65 ⇒ T12T22 = 65