A simple pendulum has time period 'T1'. The point of suspension is now moved upwards according to the relation y=KT2.(K=1m/sec2) where y is the vertical displacement. The time period now becomes 'T2'. Then find  the ratio of  T12T22  (g=10m/sec2)

on comparing with equation of motion  for vertical displacement s =ut +12at2, here initial velocity u=0    y=kt2=12at2 k=12×a but given k=1 1=12×a acceleration is a=2m/sec2 time period of simple pendulum is T1=2πlg---(1) time period of simple pendulum when it is accelerating up isT2=2πlg+a---(2) divide equation (1) by (2), and subustitute a=2 T12T22=g+ag=10+210=6/5