A simple pendulum has a time period T1 when on the earth’s surface and T2 when taken to a height R above the earth’s surface, where R is the radius of the earth. The value of T2/T1 is

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answer is D.

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Detailed Solution

If acceleration due to gravity is g at the surface of earth then at height R it value becomes g'=gRR+h2=g4T1=2πlg and T2=2πlg/4 ∴T2T1=2

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