A simple pendulum of length $$/$$ and bob mass m is displaced from its equilibrium position O to a position P so that the height of P above O is h, It is then released. What is the tension in the string when the bob passes through the equilibrium position O ? Neglect friction, v is the velocity of the bob at O.

Question

Infinity Learn · Accepted Answer

The velocity v at equilibrium position O when released from position P is given $$by12mv2=$$$$mgh$$ or $$v2=2gh$$ At O, let the tension in the string be T. Then T−$$mg=mv2/l$$ $$T=mg+mv2/l$$ $$=mg+2mghl$$ $$=mg1+2hl$$

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