First slide

Simple hormonic motion

Question

A simple pendulum is of length 50cm. Find its time period and frequency of oscillation.
(g = 9.8 m/s²).

Easy

A

2.419 sec, 0.8045Hz
B

3.219 sec, 0.5045Hz
C

5.619 sec, 0.6045Hz
D

1.419 sec, 0.7045Hz

Solution

$\large T\, = \,2\pi \sqrt {\frac{l}{g}} \, = \,2\pi \sqrt {\frac{{\frac{{50}}{{100}}}}{{9.8}}} \, = \,1.419\sec$
$\large n\, = \,\frac{1}{T}\, = \,0.7045$

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