Q.

A simple pendulum of length 90 cm is oscillating with an angular amplitude of 4o ,Then the maximum velocity of its bob is (Take g=10m/s2)

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a

π15m/s

b

π30m/s

c

π10m/s

d

π5m/s

answer is A.

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Detailed Solution

Angular amplitudeϕ=4×π180rad=π45rad.∴Linear amplitude A=ϕdAngular frequency, w=gl∴Vmax=w.A=gl×ϕl=ϕgl=π45×10×0.9m/s=π15m/s
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