A simple pendulum of length l and bob of mass m is displaced from its equilibrium position O to a position P so that height of P above O is h. It is then released. What is the tension in the string when the bob passes through the equilibrium position O? Neglect friction. V is the velocity of the bob at O

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Infinity Learn · Accepted Answer

from equation of motion $$v2=2ghfor$$ vertical circular motion, T−$$mg=mv2l$$, here T is tension in the string , m is mass of body, gg is acceleration due to gravity, v is velocity of the body, l is length of the string⇒$$T=mg+m(2gh)l$$⇒$$T=mg(1+2hl)$$

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