A simple pendulum of length $$L1$$ has a time period '$$T1$$' and another pendulum of length '$$L2$$' has time period '$$T2$$'. Then the time period of pendulum of length (L1-L2) is

Question

A simple pendulum of length $$L1$$ has a time period '$$T1$$' and another pendulum of length '$$L2$$' has time period '$$T2$$'. Then the time period of pendulum of length (L1-L2) is

Infinity Learn · Accepted Answer

time period of simple pendulum is $$T1=2$$$$π$$$$l1g$$⇒$$T12$$α$$l1---(1)$$ obtained on squaring both sides and $$2$$π, g are constants                             $$T2=2$$$$π$$$$l2g$$⇒$$T22$$α$$l2---(2)$$ l is length of pendulum ,g is acceleration due to gravity $$T=2$$$$π$$$$l1-l2g$$,  on squaring both sides,and $$2$$π, g are constants  ⇒$$T2$$α$$l1-l2$$ substituting values from equations (1),(2) $$T2$$α$$T12-T2$$ $$2$$ Tα$$T12-T22$$

A simple pendulum of length $L_{1}$ has a time period ' $T_{1}$ ' and another pendulum of length ' $L_{2}$ ' has time period ' $T_{2}$ '. Then the time period of pendulum of length ( $L_{1} - L_{2}$ ) is

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A simple pendulum of length L1 has a time period 'T1' and another pendulum of length 'L2' has time period 'T2'. Then the time period of pendulum of length (L1-L2) is

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A simple pendulum of length $L_{1}$ has a time period ' $T_{1}$ ' and another pendulum of length ' $L_{2}$ ' has time period ' $T_{2}$ '. Then the time period of pendulum of length ( $L_{1} - L_{2}$ ) is