A simple pendulum of length 'L1' has a time period 'T1' and another pendulum of length 'L2' has time period 'T2'. Then the time period of pendulum of length (L1+L2) is
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a
T1+T2
b
T1+T2
c
T1T2
d
T12+T22
answer is D.
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Detailed Solution
time period of a simple pendulum is T1=2πl1g T2=2πl2g ⇒T12αl1----(1) ⇒ T22αl2----(2) T=2πl1+l2g ⇒T2αl1+l2----(3) substitute (1),(2) in (3) T2αT12+T22 ⇒TαT12+T22