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Questions  

A simple pendulum of length l and mass m is initially at its lowest position . It is given the minimum horizontal speed necessary to move in a circular path about the point of suspension. The tension in the string at the lowest position of the bob is

a
3mg
b
4mg
c
5mg
d
6mg

detailed solution

Correct option is D

T-mg cosθ=mu2R, here T is tension in string, m is mass attached,  g is acceleration due to gravity, θ is angle made by the string with vertical  u is velocity of mass, R is radius of the circle   at lowest position θ=0,cos 0=1,thenT-mg=m5gR2R ⇒T=6mg

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What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of  10 cm (Take  g=9.8m/s2)


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