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Q.

A simple pendulum of length l and mass m is initially at its lowest position . It is given the minimum horizontal speed necessary to move in a circular path about the point of suspension. The tension in the string at the lowest position of the bob is

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a

3mg

b

4mg

c

5mg

d

6mg

answer is D.

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Detailed Solution

T-mg cosθ=mu2R, here T is tension in string, m is mass attached,  g is acceleration due to gravity, θ is angle made by the string with vertical  u is velocity of mass, R is radius of the circle   at lowest position θ=0,cos 0=1,thenT-mg=m5gR2R ⇒T=6mg
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