Questions
A simple pendulum of length ‘l’ carries a bob of mass m. If the breaking strength of the string is 2 mg, the maximum angular amplitude from the vertical can be
detailed solution
Correct option is C
When the bob moves from extreme position to mean position , it loses its potential energy and gains kinetic.Energy , speed of the bob becomes maximum and tension induced in the string also becomes maximum,.: 1/2 mV2max = mgh = mgl (1- cos θ)⇒ mV2 max /l = 2mg (1- cosθ)Tmax = mg + mV2 max / l⇒ 2mg = mg + 2mg (1-cos θ )⇒ cos θ = 1/2 ⇒ θ = 600Talk to our academic expert!
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A pendulum of length / = l m is released from . The rate of change of speed of the bob at is (g = 10 )
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