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Questions  

A simple pendulum of length ‘l’ carries a bob of mass m. If the breaking strength of the string is 2 mg, the maximum angular amplitude from the vertical can be

a
00
b
300
c
600
d
900

detailed solution

Correct option is C

When the bob moves from extreme position to mean position , it loses its potential energy and gains kinetic.Energy , speed of the bob becomes maximum and tension induced in the string also becomes maximum,.: 1/2 mV2max = mgh = mgl (1- cos θ)⇒ mV2 max /l = 2mg (1- cosθ)Tmax = mg + mV2 max / l⇒ 2mg = mg + 2mg (1-cos θ )⇒ cos θ = 1/2 ⇒ θ = 600

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Similar Questions

A pendulum of length / = l m is released from θ0 = 600. The rate of change of speed of the bob at θ = 300 is (g = 10 m/s2)


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