A simple pendulum of length $$1$$ m is allowed to oscillate with amplitude $$2$$°. It collides elastically with a wall inclined at l° to the vertical. Its time period will be: (use$$ g $$=$$ π$$2)

Question

A simple pendulum of length $$1$$ m is allowed to oscillate with amplitude $$2$$°. It collides elastically with a wall inclined at l° to the vertical. Its time period will be: (use$$ g $$=$$ π$$2)

Infinity Learn · Accepted Answer

Time period for half part:T $$=$$ $$2$$$$π$$lg $$=$$ $$2$$$$π$$lg $$=$$ $$2$$ππ $$=$$ $$2$$ secSo $$2$$° part will be covered in a time t $$=$$ $$T2$$ $$=$$ $$1$$ secFor the left l° part:θ $$=$$ θ$$0sin($$ω$$t)1$$° $$=$$ $$2$$° $$sin$$(2$$$$π$$T×$$t) ⇒$$12=$$ $$sin$$(2$$$$π$$T×$$t)⇒π$$6$$ $$=$$ π×t   ⇒ $$t=$$ $$16secTotal$$ time ⇒ $$T2+2t$$⇒$$1+2$$×$$16$$ $$=$$ $$1+13$$ $$=$$ $$43sec$$

A simple pendulum of length 1 m is allowed to oscillate with amplitude 2°. It collides elastically with a wall inclined at l° to the vertical. Its time period will be: (use g = $π^{2}$ )

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A simple pendulum of length 1 m is allowed to oscillate with amplitude 2°. It collides elastically with a wall inclined at l° to the vertical. Its time period will be: (use g = π2)

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A simple pendulum of length 1 m is allowed to oscillate with amplitude 2°. It collides elastically with a wall inclined at l° to the vertical. Its time period will be: (use g = $π^{2}$ )