A simple pendulum of length 1 m is allowed to oscillate with amplitude 2°. It collides elastically with a wall inclined at l° to the vertical. Its time period will be: (use g = π2)

Time period for half part:T = 2πlg = 2πlg = 2ππ = 2 secSo 2° part will be covered in a time t = T2 = 1 secFor the left l° part:θ = θ0sin(ωt)1° = 2° sin(2πT×t) ⇒12= sin(2πT×t)⇒π6 = π×t   ⇒ t= 16secTotal time ⇒ T2+2t⇒1+2×16 = 1+13 = 43sec