Questions
A simple pendulum of length 1 m is allowed to oscillate with amplitude 2o.It collides elastically with a wall inclined at 1o to the vertical. Its time period will be:
detailed solution
Correct option is B
Time period for half part:T=2πlg=2π1g=2ππ=2secSo 2o part will be covered in a time t=T2=1secFor the left 1o part:θ=θ0sin(ωt)1∘=2∘sin2πT×t⇒12=sin2πT×t⇒ π6=π×t⇒t=1/6sec Total time ⇒T2+2t⇒ 1+2×16=1+13=43secTalk to our academic expert!
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A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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