A simple pendulum of length 1 m is allowed to oscillate with amplitude 2o.It collides elastically with a wall inclined at 1o to the vertical. Its time period will be:  (use g=π2 )

Time period for half part:T=2πlg=2π1g=2ππ=2secSo 2o part will be covered in a time t=T2=1secFor the left 1o part:θ=θ0sin⁡(ωt)1∘=2∘sin⁡2πT×t⇒12=sin⁡2πT×t⇒ π6=π×t⇒t=1/6sec Total time ⇒T2+2t⇒ 1+2×16=1+13=43sec