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Questions  

A simple pendulum  of length 1m having bob of mass 100g is displaced through 60 from equilibrium position. The work done by gravity is  (g=10ms2)

a
-0.5J
b
0.5J
c
-0.134J
d
0.866J

detailed solution

Correct option is A

h=l−lcosθ h=l(1−cosθ) W=mghcos180 W=−mgl(1−cosθ) W=−0.1×10×1[1−12]=−0.5J

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If W1, W2 and W3 represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively (as shown) in the gravitational field of a point mass m, find the correct relation between W1, W2 and W3 


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