A simple pendulum of length 1m is taken to height R (radius of the earth) from the earth’s surface. The time period of small oscillation of the pendulum at that point is
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a
2 s
b
3 s
c
4 s
d
1 s
answer is C.
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Detailed Solution
value of g at a height h gR2R +h2 heere h=R and g becomes g4 time period of oscillation of a pendulum T=2πlg original time period 2 sec and if g decreases to g4 time period increase to two times i.e, it will be 4 sec