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Q.

A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is 1016th of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is

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a

T16

b

4T16

c

2T114

d

4T115

answer is B.

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Detailed Solution

time period of a simple pendulum is T=2πlg      ⇒Tα1g, here 2π,l are constants       Tg=T1g1----(1)   variation in acceleration due to gravity inside liquid is g1= g1−dliquiddbody g1= g1−1016=g616∴ Tg=T1g616 T=T164time period inside liquid is∴  T1=4T6s
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