Questions
A simple pendulum is oscillating with an angular amplitude of 90o as shown in fig. (4). The value of θ for
which the resultant acceleration of the bob is directed horizontally is
a
0∘
b
90∘
c
sin−1(1/3)
d
cos−1(1/3)
detailed solution
Correct option is D
See fig. (11).From figure at=gsinθand ac=v2l=2glcosθl=2gcosθNow, tanθ=acsin90∘at+accos90∘or tanθ=2gcosθgsinθ=2tanθor tan2θ=2 or sec2θ=3∴ cosθ=1/3θ=cos−1(1/3)Talk to our academic expert!
Similar Questions
A pendulum of length / = l m is released from . The rate of change of speed of the bob at is (g = 10 )
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