A simple pendulum performs SHM about x = 0 with an amplitude A and time period T. The speed of the pendulum at x = A/2 will be:

• A

  $\frac{\mathrm{A}}{\mathrm{T}}$

• B

  $\frac{\left(\sqrt{3}\right)\mathrm{\pi A}}{\mathrm{T}}$

• C

  $\frac{\mathrm{\pi A}\left(\sqrt{3}\right)}{2\mathrm{T}}$

• D

  $\frac{3{\mathrm{\pi }}^2\mathrm{A}}{\mathrm{T}}$