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Questions  

A simple pendulum performs SHM about x = 0 with an amplitude A and time period T. The speed of the pendulum at x = A/2 will be:

a
AT
b
(3)πAT
c
πA32T
d
3π2AT

detailed solution

Correct option is B

v=ωA2-y2 at  y=A2,         v=2πTA2-A24=3πAT

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