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Questions  

 A simple pendulum performs simple harmonic motion about X=0 with an amplitude A and time period T. The speed of the pendulum at 

X = A /2 will be

a
πA3/T
b
πA/T
c
πA3/2T
d
3π2A/T

detailed solution

Correct option is A

v=ωA2−X2=ωA2−A2/4=3ωA/2 =32πTA/2=πA3/T

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