A simple pendulum performs simple harmonic motion about X=0 with an amplitude A and time period T. The speed of the pendulum at X = A /2 will be

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πA3/T

πA/T

πA3/2T

3π2A/T

answer is A.

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Detailed Solution

v=ωA2−X2=ωA2−A2/4=3ωA/2 =32πTA/2=πA3/T

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