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Questions  

A simple pendulum performs simple harmonic motion about X = 0 with an amplitude A and time period T. The speed of the pendulum at X=A2 will be

a
πA3T
b
πAT
c
πA32T
d
3π2AT

detailed solution

Correct option is A

Velocity of a particle executing S.H.M. is given byv=ωa2−x2=2πTA2−A24=2πT3A24=πA3T

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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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