Q.

A simple pendulum performs simple harmonic motion about X = 0 with an amplitude A and time period T. The speed of the pendulum at X=A2 will be

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a

πA3T

b

πAT

c

πA32T

d

3π2AT

answer is A.

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Detailed Solution

Velocity of a particle executing S.H.M. is given byv=ωa2−x2=2πTA2−A24=2πT3A24=πA3T
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A simple pendulum performs simple harmonic motion about X = 0 with an amplitude A and time period T. The speed of the pendulum at X=A2 will be