A simple pendulum, suspended from the ceiling of a stationary van, has time period T. If the van starts moving with a uniform velocity the period of the pendulum will be
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a
Less than T
b
Equal to 2T
c
Greater than T
d
Unchanged
answer is D.
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Detailed Solution
T=2πlg2+a2=2πlg2+02=2πlg=TEffective value of ‘g’ remains unchanged.