A simple pendulum is suspended from the roof of a stationary car and the time period of the pendulum is 2 sec. Now the car starts moving with an acceleration which gradually increases from 0 to ‘a’. Now the time period of oscillation is found to be 2sec. Then the value of ‘a’ in m/s2 is
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answer is 2.
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Detailed Solution
When the car is stationary, T1=2πlgFor accelerated car, effective value of ‘g’ is g2+a2∴T2=2πlg2+a2∴T1T2=g2+a2g=a=gT1T24-1=10224-1m/s2=103m/s2