A simple pendulum is suspended from the roof of a stationary car and the time period of the pendulum is 2 sec. Now the car starts moving with an acceleration which gradually increases from 0 to ‘a’. Now the time period of oscillation is found to be 2sec. Then the value of ‘a’ in m/s2 is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 2.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

When the car is stationary, T1=2πlgFor accelerated car, effective value of ‘g’ is g2+a2∴T2=2πlg2+a2∴T1T2=g2+a2g=a=gT1T24-1=10224-1m/s2=103m/s2

Watch 3-min video & get full concept clarity