First slide

Electric field

Question

A simple pendulum is suspended in a lift which is going up with an acceleration of 5 m/s². An electric field of magnitude 5 N/C and directed vertically upward is also present in the lift. The charge of the bob is 1 $μ$ C and mass is 1 mg. Taking $g = π^{2}$ and length of the simple pendulum I m, the time period of the simple pendulum (in sec) is ____.

Moderate

Solution

$T = 2 π \sqrt{\frac{l}{g_{eff}}}$
$\begin{matrix} g_{eff} = g - \frac{q E}{M} + 5 = 15 - \frac{1 \times 5 \times 10^{- 6}}{1 \times 10^{- 6}} \\ g_{eff} = 10 = π^{2} \\ T = 2 \sec \end{matrix}$

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