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Q.

A simple pendulum is swinging in a vertical plane. Its highest point above the ground is 40 cm. The maximum velocity  of the pendulum is 1.96ms−1 , its lowest position above the ground is

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a

30cm

b

20.4cm

c

40cm

d

50cm

answer is B.

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Detailed Solution

V=2g(H−h) V22g=H−h⇒1.96×1.960.20.12×9.8=0.4−h 0.196=0.4−h h=0.4−0.196 = 0.204m = 20.4 cm
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A simple pendulum is swinging in a vertical plane. Its highest point above the ground is 40 cm. The maximum velocity  of the pendulum is 1.96ms−1 , its lowest position above the ground is