First slide

Applications of SHM

Question

A simple pendulum is taken from the equator to the pole. Its period

Moderate

A

Decreases
B

Increases
C

Remains the same
D

Decreases and then increases

Solution

As we go from equator to pole the value of g increases. Therefore time period of simple pendulum $(T \propto \frac{1}{\sqrt{g}})$ decreases. $(∵ T \propto \frac{1}{\sqrt{g}})$

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