Questions
A simple pendulum with bob of mass m and conducting wire of length L swings under gravity through an angle .The earth's magnetic field component in the direction perpendicular to swing is, B. Maximum potential difference induced across the pendulum is
detailed solution
Correct option is A
From figure,⇒ h=L(1−cosθ)Maximum velocity at equilibrium is given by∴ v2=2gh=2gL(1−cosθ)=2gL2sin2θ2 ⇒ v=2gLsinθ2Thus, maximum potential differenceVmax=BvL=B×2gLsinθ2L=2BLsinθ2(gL)1/2Talk to our academic expert!
Similar Questions
The diagram shows a circuit having a coil of resistance and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.
At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.
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