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Questions  

A simple pendulum with bob of mass m and conducting wire of length L swings under gravity through an angle 2θ.The earth's magnetic field component in the direction perpendicular to swing is, B. Maximum potential difference induced across the pendulum is

a
2BLsin⁡θ2(gL)1/2
b
BLsin⁡θ2(gL)
c
BLsin⁡θ2(gL)3/2
d
BLsin⁡θ2(gL)2

detailed solution

Correct option is A

From figure,⇒ h=L(1−cos⁡θ)Maximum velocity at equilibrium is given by∴     v2=2gh=2gL(1−cos⁡θ)=2gL2sin2⁡θ2 ⇒ v=2gLsin⁡θ2Thus, maximum potential differenceVmax=BvL=B×2gLsin⁡θ2L=2BLsin⁡θ2(gL)1/2

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