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Q.

A simple pendulum with a bob of mass ‘m’ oscillates from A to C and back to A such that PB is H. If the acceleration due to gravity is ‘g’, then the velocity of the bob as it passes through B is

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a

mgH

b

2gH

c

2gH

d

Zero

answer is B.

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Detailed Solution

At B, the velocity is maximum using conservation of mechanical energyΔPE=ΔKE⇒mgH=12mv2⇒v=2gH
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