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A simple pendulum with a bob of mass 'm' oscillates from A to C and back to A such that PB is H. If the acceleration due to gravity is ' g ', then the velocity of the bob as it passes through B is

a
zero
b
2gH
c
mgH
d
2gH

detailed solution

Correct option is D

At B, the velocity is maximum. Taking vertical downward motion of body from A to B, we have, u=0, a=g, s=H and v= ? As v2=u2+2as; so v2=0+2 gH or v=2 gH

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