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Trignometry
Question
sin
2
θ
=
Easy
A
1
+
cos
2
θ
2
B
1
−
cos
2
θ
2
C
1
−
cos
2
θ
D
sin
(
2
θ
)
Solution
sin
2
θ
+
cos
2
θ
=
1
sin
2
θ
=
1
-
cos
2
θ
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