In a single slit diffraction experiment first minima for λ1=660 nm coincide with first maxima for wavelength λ2 . Calculate λ2

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440 nm

445 nm

435 nm

442 nm

answer is A.

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Detailed Solution

First minima sinθ=λ1dFirst maxima sinθ1=3λ22dλ1d=3λ22dλ2=2λ13=2×6603=440nm

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