Questions  

In a single slit diffraction experiment first minima for λ1=660nm coincide with first maxima for wavelength λ2 . Calculate   λ2

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a
440 nm
b
445 nm
c
435 nm
d
442 nm
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detailed solution

Correct option is A

First minima  sinθ=λ1dFirst maxima sinθ1=3λ22dλ1d=3λ22dλ2=2λ13=2×6603=440nm

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