First slide

Diffraction

Question

In a single slit diffraction experiment first minima for $λ_{1} = 660 nm$ coincide with first maxima for wavelength $λ_{2}$ . Calculate $λ_{2}$

Moderate

A

440 nm
B

445 nm
C

435 nm
D

442 nm

Solution

First minima $sinθ = \frac{λ_{1}}{d}$
First maxima ${sinθ}^{1} = \frac{3 λ_{2}}{2 d}$
$\frac{λ_{1}}{d} = \frac{3 λ_{2}}{2 d}$
$λ_{2} = \frac{2 λ_{1}}{3} = \frac{2 \times 660}{3} = 440 nm$

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