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In single slit diffraction $a = 0.7 m m$ , $D = 2 m$ and distance of second dark band from central maxima is $0.4 c m$ . The wavelength of light is

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6500 A0

7000 A0

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detailed solution

Correct option is B

The given values are a=0.7 mm=0.7×10−3 m,D=2 m β=0.4 cm=0.4×10−2 m ,n=2 β=nλDa ⇒λ=βanD =0.4×10−2×0.7×10−32×2 ∴ λ= 7000 A0

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In single slit diffraction a=0.7 mm , D=2 m and distance of second dark band from central maxima is 0.4 cm . The wavelength of light is

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In single slit diffraction $a = 0.7 m m$ , $D = 2 m$ and distance of second dark band from central maxima is $0.4 c m$ . The wavelength of light is