Q.

In single slit diffraction pattern under bichromatic illumination. If the first minimum with the wavelength λ1 is found to be coincident with third maximum of λ2, then

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a

0.3λ1=3λ2

b

3λ1=0.3λ2

c

λ1=3.5λ2

d

3λ1=λ2

answer is C.

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Detailed Solution

y(1)min=λ1Ddy(3)max=n+12λ2Ddλ1Dd=3+12λ2Dd⇒λ1=72λ2=3.5λ2
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