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In single slit diffraction pattern under bichromatic illumination. If the first minimum with the wavelength 1 is found to be coincident with third maximum of 2, then
detailed solution
Correct option is C
y(1)min=λ1Ddy(3)max=n+12λ2Ddλ1Dd=3+12λ2Dd⇒λ1=72λ2=3.5λ2Talk to our academic expert!
Similar Questions
If I0 is the intensity of the principal maximum in the single slit diffraction pattern, then what will be its intensity when the slit width is doubled?
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