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In single slit diffraction pattern under bichromatic illumination. If the first minimum with the wavelength λ1 is found to be coincident with third maximum of λ2, then

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By Expert Faculty of Sri Chaitanya
a
0.3λ1=3λ2
b
3λ1=0.3λ2
c
λ1=3.5λ2
d
3λ1=λ2
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detailed solution

Correct option is C

y(1)min=λ1Ddy(3)max=n+12λ2Ddλ1Dd=3+12λ2Dd⇒λ1=72λ2=3.5λ2


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