In a single slit diffraction, the width of slit is 0.2 cm , focal length of lens is 40 cm and wavelength of light is 5000 A0 . The distance of first dark fringe from central maxima is

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20 μm

40 μm

100 μm

80 μm

answer is C.

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Detailed Solution

Slit width a=0.2 cm=0.2×10−2 m Focal length l=40 cm=40×10−2 m Wavelength λ=5000 A0 =5000×10−10 m β=nλfa =1×5×10−7×40×10−22×10−3 ∴ β=100 μm

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