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Questions  

In a single slit diffraction with λ = 500 nm and a slit of width 0.1 mm then width of central maxima, obtained on screen at a distance of 1 m will be

a
5 mm
b
1 mm
c
10 mm
d
2.5 mm

detailed solution

Correct option is C

Angular Position of first dark fringe is given by ∴ Width of central maximum

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