First slide

Diffraction of light-Wave Optics

Question

A single slit of width 0.20 mm is illuminated with light of wavelength 500 nm. The observing screen is placed 80 cm from the slit. The width of the central bright fringe will be

Moderate

A

1 mm
B

2 mm
C

4 mm
D

5 mm

Solution

Width of central bright fringe.
$= \frac{2 λD}{d} = \frac{2 \times 500 \times 10^{- 9} \times 80 \times 10^{- 2}}{0 .20 \times 10^{- 3}} = 4 \times 10^{- 3} m = 4 mm$

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