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Q.

A sinusoidal alternating of peak value I0 passes through a heater of resistance R. what is the mean power output of the heater?

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a

I2R2

b

I02R2

c

I32R

d

2I02R

answer is B.

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Detailed Solution

Root mean square current of the sinusoidal waveform.I=I02Power output of the heater,P=I2R=(I02)2R=I0 2R2
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