Q.
A sinusoidal current flows through a resistor of resistance R. If the peak current is Ip, then the power dissipated is
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a
Ip2R cos θ
b
12 Ip2 R
c
4π Ip2 R
d
1π Ip2 R
answer is B.
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Detailed Solution
Power I2R=Ip22R=Ip2R2
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