Q.

A sinusoidal  current flows through a resistor of resistance R. If the peak current is Ip, then the power dissipated is

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a

Ip2R cos θ

b

12 Ip2 R

c

4π Ip2 R

d

1π Ip2 R

answer is B.

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Detailed Solution

Power I2R=Ip22R=Ip2R2
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